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a. `6`b. `5`c. `4`d.`3`

Answer :

C::DSolution :

`x gt 3` <br> `log_((x + 3)/(x - 3)) 2 glt log_(2)'(x + 3)/(x - 3)` <br> Let `log_(2)'(x + 3)/(x - 3) = t` <br> `(1)/(t) lt 1 rArr x gt 3` <br> `t^(2) gt 1` <br> `rArr t gt 0 rArr gt 0` <br> `log_(2)'(x + 3)/(x - 3) gt 1` <br> `(x + 3)/(x - 3) gt 2 rArr x + 3 gt 2x - 6 rArr x lt 9` <br> so `3 lt x lt 9` <br> integral values `= 5` Transcript

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00:00 - 00:59 | welcome to download any questions we have to find the number of integers are defined the in equality in log base X + 2 upon x minus 3 or less than 2 into log x - 3 + 1 by 2 minus root x + 3 root 2 by 2 is greater than OK when firstly given equation is log x + 3 upon x minus 3 by 4 is less than 2 into log 1 by 2 x minus 3 minus log root 2 by 2 root x + 3 game ensure that from the properties of the log log bbsa can be written as one by log a base Bheem ok firstly |

01:00 - 01:59 | second one is log base e to the power n in to be this is equal to 1 by N log a base b&n into log base and this is equal to log a b to the power OK then this expression can be written as log x + 3 upon x minus 3 and 4 can be written as to a square listen to into log and one by two can be written as to the power minus one by x minus 3 minus log and 1 by root 2 by 2 1 by root 2 and 1 by root 2 can be written as 2 to the power minus 1 by 2 and into x minus 3 to the power 1 by ok |

02:00 - 02:59 | this is equal to December written as to into log at + 3 upon x minus 3 into 2 into log 2 to the power minus one can be written as minus 1 into log log base 2 x minus and this is equal to loss of 1 by 2 + 1 by 1 by 2 and log base 2 X + 3 to the power 1 by ok and this is equal to log into taking cancel out OK then X + 3 upon x minus 3 into 2 ok this is equal to minus log base 2 x minus 3 |

03:00 - 03:59 | + 2 into log base 2 X + 3 to the power 1 by and it can be written as one by log base 2 X + 3 x minus 3 minus x minus 3 X - 3 + and this is 2 into 1 by 2 log base 2 X + ok this is equal to 1 by 2 log base 2 X + 3 x minus 3 lesbian and this is equal to minus of law based 2 x minus 3 and this is |

04:00 - 04:59 | + log base 2 X + ok it can be written as one by log base 2 X + 3 x minus 3 lesan ke log base 2 game and this is equal to X + and due to plus this is x minus 3 X + 3 Y is equal to 1 by X + 3 x minus 3 list name and address - log base 2 X + 3 x ok and this is equal to 1 then |

05:00 - 05:59 | log base 2 X + 3 upon x minus 3 x square ok from here we can say that the value of x + 3 upon x minus 3 is greater than zero ok latest consider log base 2 X + 3 - 3 and this is equal to P OK then we can say that the value of a square because this is a square |